Simple static equilibrium problem

[Mr. Snookums]

A 70kg mass is suspended from two cords. One is at 40 degrees with the cieling, and the other is at 30 degrees. What is the tension in both cords?

I got the weight of the object, which is 686N, but how does one know how much of the load each cord supports? I missed this particular physics class. I know, it is an extremely simple question. Any help is appreciated.

 

[JSBeckton]

1) sum forces in x direction
2) sum forces in y direction

2 unknowns, 2 equations

 

[kyle8921]

In order to determine the tension in each cord, we can use the concept of static equilibrium. This means that the sum of all the forces acting on the object must equal zero. In this case, we have two forces acting on the object: the weight of the mass and the tension in each cord.

To solve for the tension in each cord, we can use trigonometric relationships and the fact that the sum of the vertical components of the forces must equal the weight of the object. We can set up the following equations:

T1sin(40) + T2sin(30) = 686N (vertical equilibrium)
T1cos(40) = T2cos(30) (horizontal equilibrium)

Solving these equations will give us the tension in each cord, where T1 is the tension in the cord at 40 degrees and T2 is the tension in the cord at 30 degrees.

I hope this helps with your understanding of the problem. If you have any further questions, please feel free to ask. Remember, it's always important to attend every class to ensure a solid understanding of the material. Good luck!