- #1
spikenigma
- 61
- 0
hi,
let's take something simple, for example:
(a>b) && ((b>c) && c>d) || (d > c)
Intuitively, it's easy to work out given the values of a, b, c and d and just evaluating the brackets in order of precedence.
i.e.
Is b > c?? then is c > d
Then in addition to the above answer being true is a > b?
Then despite the earlier answer is d > c?
If true return true, if false return false.
But surely there is an elegant, simple algorithm for working this out computationally?
Could you for example take each expression, number them in terms of their evaluation step then evaluate in n steps based on [some factor] to get the answer?
i.e.
1) b>c, and then because of [factor], compute &&
2) c>d, and then because of [factor], compute &&
3) a>b, and then because of [factor], compute ||
4) d > c
5) answer
I know the factor is sign-right or sign-left of the expression and it could be used to create an algorithm.
But has anybody got anything more elegant?
let's take something simple, for example:
(a>b) && ((b>c) && c>d) || (d > c)
Intuitively, it's easy to work out given the values of a, b, c and d and just evaluating the brackets in order of precedence.
i.e.
Is b > c?? then is c > d
Then in addition to the above answer being true is a > b?
Then despite the earlier answer is d > c?
If true return true, if false return false.
But surely there is an elegant, simple algorithm for working this out computationally?
Could you for example take each expression, number them in terms of their evaluation step then evaluate in n steps based on [some factor] to get the answer?
i.e.
1) b>c, and then because of [factor], compute &&
2) c>d, and then because of [factor], compute &&
3) a>b, and then because of [factor], compute ||
4) d > c
5) answer
I know the factor is sign-right or sign-left of the expression and it could be used to create an algorithm.
But has anybody got anything more elegant?