- #1
eleventhxhour
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5c) Simplify.
\(\displaystyle \frac{2x}{3y} - \frac{x^2}{4y^3} + \frac{3}{5y^4} \)This is what I did, which is wrong according to the textbook. Could someone point out what I did wrong and how to correct it? Thanks.
\(\displaystyle \frac{(2x)(4y^3)-(x^2)(3y)}{(3y)(4y^3)} + \frac{3}{5y^4}\)
\(\displaystyle \frac{8xy^3-3x^2y}{(12y^3)} + \frac{3}{5y^4}\)
\(\displaystyle \frac{(8xy^3-3x^2y)(5y^4)+(3)(12y^4)}{(12y^3)(5y^4)}\)
\(\displaystyle \frac{(40xy^7-15x^2y^5)+36y^4}{60y^8}\)
\(\displaystyle \frac{2x}{3y} - \frac{x^2}{4y^3} + \frac{3}{5y^4} \)This is what I did, which is wrong according to the textbook. Could someone point out what I did wrong and how to correct it? Thanks.
\(\displaystyle \frac{(2x)(4y^3)-(x^2)(3y)}{(3y)(4y^3)} + \frac{3}{5y^4}\)
\(\displaystyle \frac{8xy^3-3x^2y}{(12y^3)} + \frac{3}{5y^4}\)
\(\displaystyle \frac{(8xy^3-3x^2y)(5y^4)+(3)(12y^4)}{(12y^3)(5y^4)}\)
\(\displaystyle \frac{(40xy^7-15x^2y^5)+36y^4}{60y^8}\)