Simplify Fractions: (3-x)(x+2)(2x+9) < 0 | Multiply and Solve

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In summary, simplifying fractions means reducing them to their simplest form, the inequality sign "<" means "less than," we can solve expressions by multiplying and solving inequalities, there are restrictions on the values of x to avoid a denominator of 0, and we can use the given method to solve expressions such as (x+4)(x-2)(x+1) < 0.
  • #1
MrNeWBiE
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question in fractions,,,

how

2x+9/(3-x)(x+2) < 0

became



(3-x)(x+2)(2x+9) < 0 " multiply both sides "

zero is in the other side ,,,
 
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  • #2
Hi MrNeWBiE! :smile:

'cos one is (3-x)2(x+2)2 times the other … which is always positive! :wink:
 
  • #3


so i multiply both sides with ====> (3-x)^2(x+2)^2
 
  • #4
(try using the X2 tag just above the Reply box :wink:)

Yup! :biggrin:
 

FAQ: Simplify Fractions: (3-x)(x+2)(2x+9) < 0 | Multiply and Solve

What does "simplify fractions" mean in this context?

Simplifying fractions in this context refers to reducing the given expression to its simplest form, where the numerator and denominator are relatively prime (have no common factors).

What does the inequality sign "<" mean in this equation?

The inequality sign "<" means "less than," indicating that the expression on the left side is smaller than the expression on the right side.

How do you solve the expression (3-x)(x+2)(2x+9) < 0?

To solve this expression, we can use the concept of multiplying and solving inequalities. We first multiply the terms in the parentheses, and then we determine the values of x that make the expression less than 0. These values will form an interval on the number line, which will be the solution set for the inequality.

Can you provide an example of solving an expression using the given method?

Yes, for example, if we have the expression (x+4)(x-2)(x+1) < 0, we can multiply the terms to get x^3 + 3x^2 - 10x - 8 < 0. Then, we can factor this polynomial to get (x+4)(x+1)(x-2) < 0. The solutions for this inequality are x < -4, -1 < x < 2.

Are there any restrictions on the values of x in this expression?

Yes, since we are dealing with fractions, the values of x should not result in a denominator of 0. Therefore, we must exclude any values of x that would make the expressions (3-x), (x+2), or (2x+9) equal to 0.

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