- #1
noname1
- 134
- 0
2sin(wot+45)+cis(wot) to Acos(wot)
i convert it
2e^-j45 = √2/2 - j√2/2
1e^j0 = 1 - j0
adding these up i get
(√2/2 + 1) -j(√2/2)
1.707 - j.707
magnitude = √1.707²+.707² = 1.85
angle = tan^-1(.707/1.707) = 22.5
so i get 1.85cos(wot +22.5)
while the book has the answer
2.798cos(wot-30.36)
i convert it
2e^-j45 = √2/2 - j√2/2
1e^j0 = 1 - j0
adding these up i get
(√2/2 + 1) -j(√2/2)
1.707 - j.707
magnitude = √1.707²+.707² = 1.85
angle = tan^-1(.707/1.707) = 22.5
so i get 1.85cos(wot +22.5)
while the book has the answer
2.798cos(wot-30.36)