Simplifying (k + 7/k^2 + 6K + 9) + (k - 5/k^2 - 5k - 24)

  • MHB
  • Thread starter elsacozine
  • Start date
  • Tags
    Simplifying
In summary: At this point you would likely want to see if you can simplify the numerator by expanding, combining like terms and attempting to factor. :)
  • #1
elsacozine
4
0
(k + 7/k^2 + 6K + 9) + (k - 5/k^2 - 5k - 24)
 
Mathematics news on Phys.org
  • #2
Hi elsacozine and welcome to MHB! :D

Do you mean "Find the sum:

$$\dfrac{k + 7}{k^2 + 6k + 9} + \dfrac{k - 5}{k^2 - 5k - 24}$$

?
 
  • #3
Both denominators should factor nicely.
Although true, is it really relevant to finding the sum?
 
  • #4
suluclac said:
Both denominators should factor nicely.
Although true, is it really relevant to finding the sum?

Yes . . . we need to find a common denominator.

 
  • #5
greg1313 said:
Hi elsacozine and welcome to MHB! :D

Do you mean "Find the sum:

$$\dfrac{k + 7}{k^2 + 6k + 9} + \dfrac{k - 5}{k^2 - 5k - 24}$$

?

Yes; I meant that. Sorry I didn't know how to write it like that.
 
  • #6
elsacozine said:
Yes; I meant that. Sorry I didn't know how to write it like that.

Okay, so what you want to do is first factor the two denominators (if possible), so that you can determine the LCD. What do you get when factoring?
 
  • #7
MarkFL said:
Okay, so what you want to do is first factor the two denominators (if possible), so that you can determine the LCD. What do you get when factoring?

when i factor it i get:
(k + 7)/(k + 3)(k + 3) + (k - 5)/(k - 8)(k + 3)
 
  • #8
elsacozine said:
when i factor it i get:
(k + 7)/(k + 3)(k + 3) + (k - 5)/(k - 8)(k + 3)

Yes, and we can write this as:

\(\displaystyle \frac{k+7}{(k+3)^2}+\frac{k-5}{(k-8)(k+3)}\)

So, what is our LCD?
 
  • #9
MarkFL said:
Yes, and we can write this as:

\(\displaystyle \frac{k+7}{(k+3)^2}+\frac{k-5}{(k-8)(k+3)}\)

So, what is our LCD?

the LCD is (k - 8)(k + 3)^2...
so would you multiply the fractions by the their missing factors. then the denominators should be the same (LCD), then you could add the two fractions because they have common denominators?
 
  • #10
elsacozine said:
the LCD is (k - 8)(k + 3)^2...
so would you multiply the fractions by the their missing factors. then the denominators should be the same (LCD), then you could add the two fractions because they have common denominators?

Yes, although what you actually want to do is multiply each term by 1 in the form of the missing factor in that term's denominator divided by itself so that all terms have the same denominator:

\(\displaystyle \frac{k+7}{(k+3)^2}\cdot\frac{k-8}{k-8}+\frac{k-5}{(k-8)(k+3)}\cdot\frac{k+3}{k+3}\)

And so now you can combine the two terms:

\(\displaystyle \frac{(k+7)(k-8)+(k-5)(k+3)}{(k+3)^2(k-8)}\)

At this point you would likely want to see if you can simplify the numerator by expanding, combining like terms and attempting to factor. :)
 

FAQ: Simplifying (k + 7/k^2 + 6K + 9) + (k - 5/k^2 - 5k - 24)

How do you simplify the expression (k + 7/k^2 + 6K + 9) + (k - 5/k^2 - 5k - 24)?

To simplify this expression, we first need to combine like terms. This involves adding or subtracting the coefficients of terms with the same variable and exponent. In this case, the terms (k + 7) and (k) both have a k term, so we can combine them to get (2k + 7). Similarly, the terms (k^2 + 6k) and (k^2 - 5k) can be combined to get (2k^2 + k). Finally, the terms (9) and (-24) can be combined to get (-15). This gives us the simplified expression of (2k^2 + 3k - 15).

Can the expression (k + 7/k^2 + 6K + 9) + (k - 5/k^2 - 5k - 24) be further simplified?

No, the expression cannot be further simplified as we have combined all like terms and there are no common factors that can be factored out.

How do you add or subtract fractions with variables in the denominator?

To add or subtract fractions with variables in the denominator, we first need to find a common denominator. In this case, we can multiply the first fraction (k + 7/k^2 + 6K + 9) by (k - 5)/(k - 5) to get a common denominator of (k^2 + k - 63). This gives us the new expression of (k^2 + k - 63 + k^2 - 5k + 35)/(k^2 + k - 63). We can then combine like terms to get the simplified expression of (2k^2 - 4k - 28)/(k^2 + k - 63).

Can the expression (k + 7/k^2 + 6K + 9) + (k - 5/k^2 - 5k - 24) be written as a single fraction?

Yes, the expression can be written as a single fraction by finding a common denominator and combining the fractions. As shown in the previous question, the common denominator is (k^2 + k - 63). Combining the fractions gives us the expression of (2k^2 - 4k - 28)/(k^2 + k - 63).

How can simplifying this expression be useful in science?

Simplifying expressions allows us to better understand and analyze mathematical relationships in scientific experiments and theories. It can also help us solve complex equations and make predictions based on mathematical models. In the context of this specific expression, simplifying it can allow us to see the relationship between different variables and possibly make further simplifications or substitutions to better understand the underlying scientific concept.

Similar threads

Replies
2
Views
1K
Replies
4
Views
1K
Replies
4
Views
1K
Replies
1
Views
1K
Replies
7
Views
2K
Back
Top