- #1
nitai108
- 14
- 0
Can somebody please explain to me this simplification and how it's done?
[tex]\frac{n!}{(2n)!}[/tex] = [tex]\frac{1}{(2n)(2n-1)...(n+1)}[/tex]
Thanks a lot.
[tex]\frac{n!}{(2n)!}[/tex] = [tex]\frac{1}{(2n)(2n-1)...(n+1)}[/tex]
Thanks a lot.