Single conservative force acting on a particle

In summary, the conversation is about solving a potential energy function, U(x), using integration. The initial and final values for x are not specified, but it is mentioned that the initial value is 0 and the final value is unknown in part (a). The conversation also discusses confusion about using x as the integration variable and suggests using y instead. The potential energy function is ultimately written as U(x) = 1/2Ax^2 + 1/3BX^3 with a lower limit of 0.
  • #1
Robb
225
8

Homework Statement


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Homework Equations


U(final)(x)= (-) Integral F dx + U(initial)
Integration from (x-initial to x-final)

The Attempt at a Solution



U(final)(x)= (-) integral (-Ax+Bx^2)dx

Not sure on limits of integration
 
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  • #2
You have to start the integration at a place where U is known. What place is that?

If you want to give the value of U at location coordinate x, what is the upper limit of integration?
 
  • #3
Not sure. Lower = 0. upper x=2.00 & x=3.00?
 
  • #4
I was referring to part (a). There is no 2.00 or 3.00 in part (a). Once you have solved part (a), part (b) is just a question of substitution and subtraction.
I think you may be confusing yourself by mislabelling your integration variables.
You wrote:

U(final)(x)= (-) Integral F dx + U(initial)

That can't be right because the LHS depends on X while the RHS does not. By using x as the integration variable you make it disappear once the integral is taken. Instead use y as your integration variable and x as one of your limits of integration. Which one?
 
  • #5
So, my potential energy function is U(x) = (-) integral F dx = (-) integral (-Ax+Bx^2) dx = 1/2Ax^2 + 1/3 BX^3

U=0 @ x=0

Though I am seeing this as a lower limit
 

FAQ: Single conservative force acting on a particle

What is a single conservative force?

A single conservative force is a type of force that acts on a particle and has the property that the work done by the force on the particle is independent of the path taken by the particle. This means that the work done by the force on the particle only depends on the initial and final positions of the particle, not the path it takes to get there.

How is a conservative force different from a non-conservative force?

A conservative force is different from a non-conservative force in that the work done by a conservative force only depends on the initial and final positions of the particle, while the work done by a non-conservative force also depends on the path taken by the particle. Additionally, a conservative force conserves mechanical energy, while a non-conservative force does not.

What are some examples of conservative forces?

Some examples of conservative forces include gravity, electrostatic forces, and Hooke's law forces (such as the force exerted by a spring). These forces are considered conservative because they conserve mechanical energy and the work done by these forces is path independent.

How is the work done by a single conservative force calculated?

The work done by a single conservative force on a particle is calculated using the formula W = -ΔU, where W is the work done, ΔU is the change in potential energy of the particle, and the negative sign indicates that work is being done on the particle by the force. This formula is derived from the definition of a conservative force, which states that the work done by the force is equal to the negative change in potential energy.

Can a single conservative force change the kinetic energy of a particle?

No, a single conservative force cannot change the kinetic energy of a particle. This is because conservative forces only affect the potential energy of a particle, not its kinetic energy. Therefore, the total mechanical energy (the sum of kinetic and potential energy) of a particle remains constant when acted upon by a single conservative force.

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