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[SOLVED] Single-Slit Diffraction
You have been asked to measure the width of a slit in a piece of paper. You mount the paper 80.0 centimeters from a screen and illuminate it from behind with laser light of wavelength 633 nanometers (in air). You mark two of the intensity minima as shown in the figure, and measure the distance between them to be 17.9 millimeters.
If the entire apparatus were submerged in water, would the width of the central peak change?
a.The width would increase.
b.The width would decrease.
c.The width would not change.
asin(theta) = m(lambda)
Well for the first part of this question I found the width of this slit in air to be 170 micrometers.
I know this is a conceptual question, but I need help understanding exactly what happens. I know the index of refraction changes from 1 to 1.33.
Homework Statement
You have been asked to measure the width of a slit in a piece of paper. You mount the paper 80.0 centimeters from a screen and illuminate it from behind with laser light of wavelength 633 nanometers (in air). You mark two of the intensity minima as shown in the figure, and measure the distance between them to be 17.9 millimeters.
If the entire apparatus were submerged in water, would the width of the central peak change?
a.The width would increase.
b.The width would decrease.
c.The width would not change.
Homework Equations
asin(theta) = m(lambda)
The Attempt at a Solution
Well for the first part of this question I found the width of this slit in air to be 170 micrometers.
I know this is a conceptual question, but I need help understanding exactly what happens. I know the index of refraction changes from 1 to 1.33.