- #1
kurious
- 641
- 0
If I use E x t = h bar
and put t = age of universe in seconds = 10^ 18 seconds,
E x 10^18 = 10 ^ -34 gives E = 10^ -52 Joules.
So if an oscillator of some sort in the early universe absorbed a photon,
and emitted the energy of that photon today, there would be an uncertainty in the photon energy of 10 ^ -52 Joules.This energy corresponds to a wavelength of 10 ^ 26 metres - the current size of the universe.
This makes sense because a particle can't exist outside of the universe -
the maximum uncertainty in its position has to equal the size of the universe.
So can the uncertainty principle be used to measure the size of the universe?
and put t = age of universe in seconds = 10^ 18 seconds,
E x 10^18 = 10 ^ -34 gives E = 10^ -52 Joules.
So if an oscillator of some sort in the early universe absorbed a photon,
and emitted the energy of that photon today, there would be an uncertainty in the photon energy of 10 ^ -52 Joules.This energy corresponds to a wavelength of 10 ^ 26 metres - the current size of the universe.
This makes sense because a particle can't exist outside of the universe -
the maximum uncertainty in its position has to equal the size of the universe.
So can the uncertainty principle be used to measure the size of the universe?