- #1
Ibraheem
- 51
- 2
Hello,
In this simulation (link is below) the graph of the potential energy with respect to position U(x) when there is no friction on the ramp looks like the graph of potential energy of Hooke's Law spring U(x)=(1/2)KX^2). For the spring, the negative of the derivative is equal to the horizontal restoring force. So what restoring force is the negative derivative of potential energy graph for the skater in the simulation?I have included a picture of the simulation along with the potential energy U(x) graph.
Simulation:
http://phet.colorado.edu/en/simulation/energy-skate-park
In this simulation (link is below) the graph of the potential energy with respect to position U(x) when there is no friction on the ramp looks like the graph of potential energy of Hooke's Law spring U(x)=(1/2)KX^2). For the spring, the negative of the derivative is equal to the horizontal restoring force. So what restoring force is the negative derivative of potential energy graph for the skater in the simulation?I have included a picture of the simulation along with the potential energy U(x) graph.
Simulation:
http://phet.colorado.edu/en/simulation/energy-skate-park