- #1
wiggle
- 2
- 0
Homework Statement
A 50Kg skier skies down a 25 degree slope. at the top of the slope her speed is 4m/s and accelerates down the hill. the coefficient of friction is 0.12 between skies and snow. ignoring air resistance calculate her speed at point that is displaced 60m downhill.
Homework Equations
E=KE+PE
E=.5*m*V^2+m*g*h
The Attempt at a Solution
I believe I solved it correctly using E0=.5(50)4^2+50(9.8)(60sin(25)) and getting 12650
then setting 12650 = .5*m*Vf^2 and I'm getting Vf=22.5 m/s
However I'm unsure how to go about solving while taking into consideration the friction, since there is a non conservative force at work using KE0+PE0=KEf+PEf would get me close but not all the way there.