- #1
barzi2001
- 10
- 0
Hi all. I'm struggling to understand how and where the friction forces that appear on the motion of a wheel on a flat surface, but I don't know if I understand it properly. I hope that you can help me. I try to describe the problem as follows.
When a wheel is not moving, and there are no forces/torques applied on that, at the contact point of the wheel with the ground (let's call it P) the reaction force points "upwards", it passes for the center of the wheel and it has the same magnitude of the weight force. Hence, the resulting force is zero as well as the resulting torque.
When a torque is applied, let's say clockwise, it generate a horizontal force F that is applied to the contact point P, and such force F points toward left. The magnitude of such force F is equal to T/r, where T is the applied torque and r is the wheel radius. The reaction force at the contact point P in this case will point toward up-right. This means that the reaction force can be decomposed in two components: one horizontal and one vertical. The vertical force (which points upwards) passes again for the center of the wheel, while the horizontal force (which points toward right) "push" the wheel toward right (I assumed that F is smaller that the static sliding friction). In this case, both the horizonal and vertical components of the reaction force are applied at the point P.
By including also the rolling friction, we have, like before, that the reaction force at the point P points again in up-right direction. Again, this force can be decomposed in a horizontal and vertical component. The difference with respect to the previous case is that now the horizontal component is applied to the point P while the vertical component is applied in a point P' that is located slightly to the right of P. Since the vertical component of the reaction force is applied at P', it does not passes for the center of the wheel, and then it generates a resistance torque, while the horizontal force, being applied to P, does the same job as the previous case (pushes the wheel toward right).
In synthesis, by combining the two frictions in one shot, can I say that it can be represented as a reaction force that points up-right, but the horizontal component is applied to P while the vertical component is applied to P'? But where it is applied such reaction force that include both the rolling and the sliding frictions?
And moreover, if the force F in the contact point P due to the applied torque is greater than the static friction, I imagine that the wheel would rolls without translating, but after some time it will it stop because of a vertical component applied to P'?
Finally, when I use a brake (for example a disk brake), is equivalent to say that I'm adding an additional friction that points toward left and thus it opposes to the motion of the wheel?
I hope I provided a good description of the example. Looking forward for your answer.
When a wheel is not moving, and there are no forces/torques applied on that, at the contact point of the wheel with the ground (let's call it P) the reaction force points "upwards", it passes for the center of the wheel and it has the same magnitude of the weight force. Hence, the resulting force is zero as well as the resulting torque.
When a torque is applied, let's say clockwise, it generate a horizontal force F that is applied to the contact point P, and such force F points toward left. The magnitude of such force F is equal to T/r, where T is the applied torque and r is the wheel radius. The reaction force at the contact point P in this case will point toward up-right. This means that the reaction force can be decomposed in two components: one horizontal and one vertical. The vertical force (which points upwards) passes again for the center of the wheel, while the horizontal force (which points toward right) "push" the wheel toward right (I assumed that F is smaller that the static sliding friction). In this case, both the horizonal and vertical components of the reaction force are applied at the point P.
By including also the rolling friction, we have, like before, that the reaction force at the point P points again in up-right direction. Again, this force can be decomposed in a horizontal and vertical component. The difference with respect to the previous case is that now the horizontal component is applied to the point P while the vertical component is applied in a point P' that is located slightly to the right of P. Since the vertical component of the reaction force is applied at P', it does not passes for the center of the wheel, and then it generates a resistance torque, while the horizontal force, being applied to P, does the same job as the previous case (pushes the wheel toward right).
In synthesis, by combining the two frictions in one shot, can I say that it can be represented as a reaction force that points up-right, but the horizontal component is applied to P while the vertical component is applied to P'? But where it is applied such reaction force that include both the rolling and the sliding frictions?
And moreover, if the force F in the contact point P due to the applied torque is greater than the static friction, I imagine that the wheel would rolls without translating, but after some time it will it stop because of a vertical component applied to P'?
Finally, when I use a brake (for example a disk brake), is equivalent to say that I'm adding an additional friction that points toward left and thus it opposes to the motion of the wheel?
I hope I provided a good description of the example. Looking forward for your answer.