- #1
DeanBH
- 82
- 0
I have a question that i am struggling to come to terms with. I know how to get the answer but i am not 100% sure why what i am doing works.
The question :
A smooth plane is inclined at X degrees to the horizontal.
A block of mass 5KG is held at rest on the plane by a horizontal force of magnitude 168N.
Find :
Angle X
The force on Normal on the block.
Ok, so far i have this.
i separated the horizontal force of 168N into a force horizontal and a force parralel to the plane.
Horizontal : 168CosX = 5gsinX
parallel : N = mgcosX + 168sin X
Now somehow, and this is the part i do not understand 100%
you get to the equation
5gcosX=168cosX
sinX/cosX=168/5g
tanX=168/5g
so then X is the tan^-1 of (168/5g).
and then you put it back in the parallel equation to find N, the normal.
Can someone explain to me how you come about reaching these equations :
5gcosX=168cosX
sinX/cosX=168/5g
tanX=168/5g
thank you.
The question :
A smooth plane is inclined at X degrees to the horizontal.
A block of mass 5KG is held at rest on the plane by a horizontal force of magnitude 168N.
Find :
Angle X
The force on Normal on the block.
Ok, so far i have this.
i separated the horizontal force of 168N into a force horizontal and a force parralel to the plane.
Horizontal : 168CosX = 5gsinX
parallel : N = mgcosX + 168sin X
Now somehow, and this is the part i do not understand 100%
you get to the equation
5gcosX=168cosX
sinX/cosX=168/5g
tanX=168/5g
so then X is the tan^-1 of (168/5g).
and then you put it back in the parallel equation to find N, the normal.
Can someone explain to me how you come about reaching these equations :
5gcosX=168cosX
sinX/cosX=168/5g
tanX=168/5g
thank you.