- #1
H_man
- 145
- 0
Hi All...
I am really confused about the mechanism of loss of energy when an EM wave hits a metal surface.
I always thought the reflection was due to the motion of the electrons in the metal (due to the electric field of the wave). Which suggests that resistive losses would come from the E field of the wave doing work.
However, I also know the magnetic field penetrates in the manner of the skin effect and also induces currents to cancel the changing B field.
So it seems to me that both field contribute to currents and hences losses in a non-ideal conductor.
The energy stored in each of the fields in the wave is equal so I would assume that the loss caused by each would similar?
Can anyone relieve my confusion Or even just tell me of a good textbook where this is treated. I've been looking but I can't find a clear answer.
I don't think looking at this from the view of individual photons is going to help :-(
Thanks in advance
Harry
I am really confused about the mechanism of loss of energy when an EM wave hits a metal surface.
I always thought the reflection was due to the motion of the electrons in the metal (due to the electric field of the wave). Which suggests that resistive losses would come from the E field of the wave doing work.
However, I also know the magnetic field penetrates in the manner of the skin effect and also induces currents to cancel the changing B field.
So it seems to me that both field contribute to currents and hences losses in a non-ideal conductor.
The energy stored in each of the fields in the wave is equal so I would assume that the loss caused by each would similar?
Can anyone relieve my confusion Or even just tell me of a good textbook where this is treated. I've been looking but I can't find a clear answer.
I don't think looking at this from the view of individual photons is going to help :-(
Thanks in advance
Harry