- #1
JackieAnne
- 7
- 0
Use implicit differentiation to find dy/dx.
y is a differentiable function of x
2y^2+4xsiny = cos4x
Here is what I did:
4y*dy/dx + 4siny+ 1/cosy*dy/dx = -sin4x + 4
4y*dy/dx + 1/cosy*dy/dx = -sin4x - 4siny + 4
dy/dx(4y + 1/cosy) = -sin4x - 4siny + 4
dy/dx = (-sin4x - 4siny + 4) / (4y + (1/cosy))
My answer is incorrect. Can anyone tell me where I went wrong and what the answer should be? Thanks
y is a differentiable function of x
2y^2+4xsiny = cos4x
Here is what I did:
4y*dy/dx + 4siny+ 1/cosy*dy/dx = -sin4x + 4
4y*dy/dx + 1/cosy*dy/dx = -sin4x - 4siny + 4
dy/dx(4y + 1/cosy) = -sin4x - 4siny + 4
dy/dx = (-sin4x - 4siny + 4) / (4y + (1/cosy))
My answer is incorrect. Can anyone tell me where I went wrong and what the answer should be? Thanks