- #1
surferbarney0729
- 32
- 0
So with the equation MU=ln(C1)+ln(160-1.1C1)
the derivative is 1/C1 - 1.1/(160-1.1C1)
How does one solve and identify the derivative instead being seen and written as
2.2C1 = 160
What are the steps taken to get to the latter derivative. the second format was much easier to solve the final equation, but I am not sure how to 2.2C1 = 160 was found
Any help?
the derivative is 1/C1 - 1.1/(160-1.1C1)
How does one solve and identify the derivative instead being seen and written as
2.2C1 = 160
What are the steps taken to get to the latter derivative. the second format was much easier to solve the final equation, but I am not sure how to 2.2C1 = 160 was found
Any help?