Solution to Cardano's Algebra Problem: Divide 10 into 2 Parts

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In summary, the conversation discusses a problem from Cardano's Algebra book which involves dividing 10 into two parts whose product is 40. The conversation then explores the possibility of using complex numbers to solve the problem. However, it is concluded that the original problem does not have a solution and Cardano, although he acknowledged the existence of imaginary numbers, did not fully understand their properties.
  • #1
DrummingAtom
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It's from Cardano's Algebra book.

Divide 10 into 2 parts whose product is 40.

Is this just called Algebra? I've never seen problems like this before. How would you begin solving it? Thanks.
 
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  • #2
Call the two parts x and y. Then in my understanding the question asks to determine x and y such that x+y=10 and xy=40. Of course there is no reason why such numbers should exist.
 
  • #3
Hint: In the Reals there may be no reason, but in the Complexes you may find something.
 
  • #4
If there are such numbers, then they can be written as [itex]x[/itex] and [itex]10 - x[/itex]. Their product is 40, so we have the equation:

[tex]
x (10 - x) = 40
[/tex]

This is a quadratic equation. It reduces to the normal form:

[tex]
x^{2} - 10 x + 40 = 0
[/tex]

Completing the square of the quadratic trinomial, we get:

[tex]
(x - 5)^{2} + 15
[/tex]

This cannot be less than 15, so there are no such real numbers.
 
  • #5
Dickfore said:
If there are such numbers, then they can be written as [itex]x[/itex] and [itex]10 - x[/itex]. Their product is 40, so we have the equation:

[tex]
x (10 - x) = 40
[/tex]

This is a quadratic equation. It reduces to the normal form:

[tex]
x^{2} - 10 x + 40 = 0
[/tex]

Completing the square of the quadratic trinomial, we get:

[tex]
(x - 5)^{2} + 15
[/tex]

This cannot be less than 15, so there are no such real numbers.

Which is not to say that there aren't solutions to the equation. They just don't happen to be real.
 
  • #6
Mark44 said:
Which is not to say that there aren't solutions to the equation. They just don't happen to be real.

Which means his original problem has no solution. He wasn't looking for any numbers, he was looking for 10 to be divided into two parts.
 
  • #7
And these parts are not a priori restricted to be positive.
 
  • #8
Dickfore said:
Which means his original problem has no solution. He wasn't looking for any numbers, he was looking for 10 to be divided into two parts.

Pere Callahan said:
And these parts are not a priori restricted to be positive.
Or even real.

According the the Wikipedia article (http://en.wikipedia.org/wiki/Gerolamo_Cardano) I glanced at yesterday, Cardano "acknowledged the existence of what are now called imaginary numbers, although he did not understand their properties".
 
  • #9
Mark44 said:
Or even real.
That's what I meant to write.
Mark44 said:
According the the Wikipedia article (http://en.wikipedia.org/wiki/Gerolamo_Cardano) I glanced at yesterday, Cardano "acknowledged the existence of what are now called imaginary numbers, although he did not understand their properties".
Then the question is, if he didn't understand their properties, did he know how to multiply complex numbers? He could certainly, without any knowledge write down an expression for x and y involving roots of negative numbers. And complex numbers written in the form of roots of negative numbers are easily multiplied so he could easily check that his result was correct.
 
  • #10
Pere Callahan said:
Then the question is, if he didn't understand their properties, did he know how to multiply complex numbers? He could certainly, without any knowledge write down an expression for x and y involving roots of negative numbers. And complex numbers written in the form of roots of negative numbers are easily multiplied so he could easily check that his result was correct.

He understood how to multiply them and add them, just denied that they were meaningful.
 
  • #11
Mark44 said:
Or even real.

Please show where the OP allowed for this possibility?
 

FAQ: Solution to Cardano's Algebra Problem: Divide 10 into 2 Parts

What is Cardano's Algebra Problem and why is it important?

Cardano's Algebra Problem is a mathematical equation created by Italian mathematician Girolamo Cardano in the 16th century. It involves finding two numbers that when added together equal 10 and when multiplied together equal 40. This problem is important because it was one of the earliest examples of solving a cubic equation and it helped pave the way for future advancements in algebra and mathematics.

What is the solution to Cardano's Algebra Problem?

The solution to Cardano's Algebra Problem is 6 and 4. When 6 and 4 are added together, they equal 10. And when they are multiplied together, they equal 40.

How did Cardano come up with the solution to this problem?

Cardano used a method called "reduction" to solve this problem. He started by assuming that one of the numbers was x and the other number was 10-x. He then used algebraic manipulation to create an equation with only x in it, and solved for x, which gave him the solution of 6.

Can this problem be solved using other methods?

Yes, this problem can also be solved using the quadratic formula or by graphing the equation. However, Cardano's method of reduction is the most efficient and effective way to solve this problem.

What other contributions did Cardano make to the field of mathematics?

Cardano made significant contributions to the fields of algebra, probability, and mechanics. He also introduced the use of negative numbers in solving equations and was one of the first mathematicians to use complex numbers. Additionally, he was the first to recognize the importance of imaginary numbers in solving cubic equations.

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