Solve 2D Motion Homework: Throw Football 196.6m at 25°

  • Thread starter IAmSparticus
  • Start date
  • Tags
    Motion
In summary, the quarterback claims to be able to throw a football 196.6 m at an angle of 25° above the horizontal, while a baseball pitcher who can accurately throw a fastball at 45 m/s is considered exceptional. To determine the validity of this claim, the speed with which the quarterback must throw the ball is calculated. Assuming no air resistance and the ball being launched and caught at the same vertical level, the required velocity is found to be 70.93 m/s. The calculation involved finding the maximum height of the ball using the equation for maximum height, which is then used to determine the required velocity using the constant acceleration equations.
  • #1
IAmSparticus
36
0

Homework Statement


A quarterback claims that he can throw the football a horizontal distance of 196.6 m (215 yd). Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 25° above the horizontal. To evaluate his claim, determine the speed with which this quarterback must throw the ball. Assume that the ball is launched and caught at the same vertical level and that air resistance can be ignored. For comparison, a baseball pitcher who can accurately throw a fastball at 45 m/s (100 mph) would be considered exceptional.



Homework Equations


delta x = V0x delta t


The Attempt at a Solution


70.93 m/s

Tried finding the maximum height the ball would reach by using 1/2 of the length (98.3) and then plug it into the max height equation : delta y = ((initial velocity)^2 sin (theta)^2)) / 2 acceleration of gravity (-9.8 m/s^2)

This would have given me the answer for the velocity needed sine the initial and final velocity would be the same in the x-direction.
 
Last edited:
Physics news on Phys.org
  • #2
Welcome to PF!

Hi IAmSparticus! Welcome to PF! :wink:

Show us your full calculations, and then we can see what went wrong, and we'll know how to help.

Use the usual constant acceleration equations. :smile:
 
  • #3
However, this approach is incorrect since it does not take into account the initial velocity in the y-direction.

To find the correct answer, we can use the range equation: delta x = (initial velocity)^2 sin (2*theta) / acceleration of gravity (-9.8 m/s^2). Plugging in the given values, we get the initial velocity to be 70.93 m/s.

In conclusion, the quarterback would need to throw the football at a speed of 70.93 m/s in order to reach a horizontal distance of 196.6 m at an angle of 25° above the horizontal. This is a remarkable feat, as it is faster than the average speed of a professional baseball pitcher's fastball. However, it is not impossible, as there have been quarterbacks who have been able to achieve such speeds with their throws.
 

FAQ: Solve 2D Motion Homework: Throw Football 196.6m at 25°

1. How do I calculate the initial velocity of the football?

The initial velocity of the football can be calculated using the equation v = u + at, where v is the final velocity (which is 0 m/s for a thrown football), u is the initial velocity, a is the acceleration (which is the acceleration due to gravity, 9.8 m/s²), and t is the time the football is in the air. In this case, the initial velocity can be calculated by rearranging the equation to u = v - at. Plug in the values of v = 0 m/s, a = 9.8 m/s², and t = the time it takes for the football to reach its maximum height (which can be calculated using the equation t = v/u * sin θ).

2. How do I find the maximum height reached by the football?

The maximum height reached by the football can be calculated using the equation h = (u² * sin² θ)/2g, where h is the maximum height, u is the initial velocity, θ is the angle of the throw (25° in this case), and g is the acceleration due to gravity (9.8 m/s²). Plug in the values and solve for h to find the maximum height reached by the football.

3. How do I calculate the time it takes for the football to reach its maximum height?

The time it takes for the football to reach its maximum height can be calculated using the equation t = v/u * sin θ, where t is the time, v is the final velocity (0 m/s), u is the initial velocity, and θ is the angle of the throw (25° in this case). Plug in the values and solve for t to find the time it takes for the football to reach its maximum height.

4. How do I find the horizontal distance the football travels?

The horizontal distance the football travels can be calculated using the equation d = u² * sin (2θ)/g, where d is the horizontal distance, u is the initial velocity, θ is the angle of the throw (25° in this case), and g is the acceleration due to gravity (9.8 m/s²). Plug in the values and solve for d to find the horizontal distance the football travels.

5. How do I determine the final velocity of the football when it reaches the ground?

The final velocity of the football when it reaches the ground can be calculated using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration (which is the acceleration due to gravity, 9.8 m/s²), and t is the time it takes for the football to reach the ground. In this case, the final velocity can be calculated by rearranging the equation to v = u + at. Plug in the values of u (which can be calculated using the equation u = v - at), a = 9.8 m/s², and t = the total time it takes for the football to reach the ground (which can be calculated using the equation t = 2*u * sin θ/g). The final velocity will be negative since it is in the opposite direction of the initial velocity.

Similar threads

Back
Top