That would give you the total charge, not the charge per ball.logearav said:what is the need for dividing by 3. why not simply add the charges q1+q2+q3
No, why would they? They retain no "memory" of their initial charges.logearav said:if they are separated won't they get their initial charges?
Solving an electrostatics problem involves identifying the known and unknown variables, using the appropriate equations and principles of electrostatics, and solving for the unknown variable using algebraic manipulation.
Conductors are materials that allow the flow of electric charge, while insulators are materials that do not allow the flow of electric charge. In electrostatics problems, conductors are typically represented as equipotential surfaces, while insulators are represented as regions with no electric charge.
Electric potential can be calculated using the equation V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the electric charge, and r is the distance from the electric charge.
The unit of electric field is Newtons per Coulomb (N/C). This represents the force experienced by a unit positive charge placed in the electric field.
You can check your solution by ensuring that it satisfies all of the given conditions and equations, and by checking that the units are consistent. You can also use a calculator or simulation software to verify your solution.