Solve 6th Grade Sequence: 1,5,13,25,41,61

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The discussion revolves around solving a 6th-grade math sequence: 1, 5, 13, 25, 41, 61. Participants identify a pattern in the differences between the numbers, noting they increase by multiples of four. The challenge lies in formulating an equation to represent the sequence. One suggested equation is a_{n}=n^{2}+(n-1)^{2}. The thread highlights the difficulty of the assignment and seeks further clarification and assistance.
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Help, anyone. I am very new to this forum and am really here trying to help my son with his wicked 6th grade homework. His teacher is in my opinion, assigning problems that are way too difficult. I was hoping someone here could maybe help. The problem is as follows: The students are given the sequence 1,5,13,25,41,61 and have to come up with an equation to solve the sequence. Any ideas? This should be easy for you all. But for me, who was good at math at one time, this is beyond what I can come up with. Any help would be appreciated!
 
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Hint: what's the difference between 5 and 1? 13 and 5? 25 and 13? 41 and 25? 61 and 41?
see the pattern?

oh, and Hi! Welcome to PF! :smile:
 
Hmm, I see a pattern too. Counting up from zero 1, 4, 8, 12, 16, 20...
 
I see the pattern as well, they are all separated by multiples of four, but it's coming up with the equation that is the problem. Any more hints? Maybe it will job something in my distance math past!
 
Sorry about that, I bungled up a bit..
 
My mistake everyone,

I am going to post in the homework section. Thanks all. I also stated the problem incorrectly.

debra
 
From what I can see, the terms fulfill:
a_{n}=n^{2}+(n-1)^{2}
 

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