Solve a Simple Physics Problem for High School: Pelican and Falling Fish"

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In summary, a small fish dropped by a pelican that is rising steadily at 0.41m/s. After 1.8s, the velocity of the fish is unknown. Some steps and formulae are needed to solve this problem. One possible approach is to use the formula vf=vi+at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time. For part b, the formula s=(vi+vf/2)*t or s=vit+1/2at^2 can be used, where s is the distance, vi is the initial velocity, vf is the final velocity, and t is the time. It is important to show some work
  • #1
playa007
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i have just started physics in high school and i got this problem i want some help on this question:

A small fish is dropped by a pelican that is rising steadily at 0.41m/s.
a)After 1.8s, what is the velocity of the fish? Answer in units of m/s
b)How far below the pelican is the fish after the 1.8s? Answer in units of m.

if anyone can show me the steps and formulae, thanks.
 
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  • #2
what steps have you taken so far? most people on this board like to see that you put some work in a problem before submitting it for help. Here is a hint:

What effect does the fact that the pelican is rising have on the fall of the fish? Is gravity affected when you are moving against gravity at a gentle constant velocity?

~Lyuokdea
 
  • #3
vi= 0.41 m/s
t-1.8s
vf= ?
a=9.8 m/s
therefore u use vf=vi+at
that is what i think i not quite sure for part a.
for part b u use s=(vi+vf/2)*t or s=vit+1/2at^2
 

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1. What is a "Very Simple Physics Problem"?

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