Solve Binomial Expansion Homework: (a) (1-x6)4, (b), (c) |x|<1

In summary, to expand (1-x6)4, the result is 1-4x6+6x12-4x18+x24. The coefficient of xr in the expansion of (1-x)-4 for |x|<1 is given by (r+1)(r+2)(r+3)/6. Using this formula, the coefficient of x^8 in the expansion of ((1-x6)/(1-x))4 for |x|<1 is 125.
  • #1
chrisyuen
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0

Homework Statement



(a) Expand (1-x6)4
(b) Find the coefficient of xr, where r is a non-negative integer, in the expansion of (1-x)-4 for |x|<1.
(c) Using (a) and (b), or otherwise, find the coefficient of x^8 in the expansion of ((1-x6)/(1-x))4 for |x|<1.

(Answers:
(a) 1-4x6+6x12-4x18+x24
(b) (r+1)(r+2)(r+3)/6
(c) 125)

Homework Equations



Binomial Expansion: n(n-1)...(n-r+1)*xr/r!

The Attempt at a Solution



I can solve parts (a) and (b) but not part (c).

I tried (-4)(2+3)(2+2)(2+1)/6 = -40 but not correct.

Can anyone tell me how to solve it?

Thank you very much!
 
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  • #2
Hi chrisyuen! :smile:
chrisyuen said:
(c) Using (a) and (b), or otherwise, find the coefficient of x^8 in the expansion of ((1-x6)/(1-x))4 for |x|<1.

(Answers:
(a) 1-4x6+6x12-4x18+x24
(b) (r+1)(r+2)(r+3)/6
(c) 125)

I tried (-4)(2+3)(2+2)(2+1)/6 = -40 but not correct.

Yes, that's x6 times x2

now what about 1 times x8? :wink:
 
  • #3
tiny-tim said:
Hi chrisyuen! :smile:


Yes, that's x6 times x2

now what about 1 times x8? :wink:

Yes, I got it!

Thank you very much!
 

FAQ: Solve Binomial Expansion Homework: (a) (1-x6)4, (b), (c) |x|<1

What is a binomial expansion?

A binomial expansion is a mathematical process used to expand a binomial expression to a higher power. It is commonly used to simplify complex algebraic expressions.

How do I solve a binomial expansion homework?

To solve a binomial expansion homework, you can use the binomial theorem or the Pascal's triangle method. You can also use online calculators or software programs to help you solve the expansion.

What is the expansion of (1-x6)4?

The expansion of (1-x6)4 is 1 - 4x6 + 6x12 - 4x18 + x24.

How do I solve (b) and (c) when |x|<1?

When |x|<1, you can use the formula (1+x)n = 1 + nx + (n(n-1)/2!)x2 + (n(n-1)(n-2)/3!)x3 + ... + (n(n-1)(n-2)...(n-r+1)/r!)xr. Substitute the given values of n, x, and r to solve for the expansion.

What is the significance of |x|<1 in binomial expansion?

The value of |x|<1 is significant in binomial expansion because it ensures that the expansion will converge and not diverge. If |x| is greater than or equal to 1, the expansion will not converge and will result in an infinite series.

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