- #1
Fabio010
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Find the first radius, the energy of "connection" and the wavelenght of the first risk of Lyman series of a hydrogen atom that electron has been "replaced" for a meson with negative charge with a mass 207*electron mass. Radius:
r = (h^2*n^2)/(4pi^2*e^2*k*me)
we know all constants so we just replace me for 207me and the solution is 2.6*10^-13m
in book solution the result is 2.8*10^-13m (i don't think that the difference is not significant)Energy of "connection"
E = - (ke^2)/(2r)
as we now radius, the energy is -4.4 *10^-16 J
in book is = -4.04*10^-16 JWavelenght (the problem)
E = hc/l (l = wavelenght)
l = hc/(4.4 *10^-16) = 4.5 * 10^-10 m 0.45 nm
but in book solutions l = 0.656nm
the problem is that with book results
l = hc/(4.04*10^-16) = 4.9 * 10^-10 m 0.49 nmSo i guess that i resolved it in a wrong way.PS: Sorry my english.
r = (h^2*n^2)/(4pi^2*e^2*k*me)
we know all constants so we just replace me for 207me and the solution is 2.6*10^-13m
in book solution the result is 2.8*10^-13m (i don't think that the difference is not significant)Energy of "connection"
E = - (ke^2)/(2r)
as we now radius, the energy is -4.4 *10^-16 J
in book is = -4.04*10^-16 JWavelenght (the problem)
E = hc/l (l = wavelenght)
l = hc/(4.4 *10^-16) = 4.5 * 10^-10 m 0.45 nm
but in book solutions l = 0.656nm
the problem is that with book results
l = hc/(4.04*10^-16) = 4.9 * 10^-10 m 0.49 nmSo i guess that i resolved it in a wrong way.PS: Sorry my english.