- #1
find_the_fun
- 148
- 0
Solve given differential equation by separation of variables
\(\displaystyle \frac{dy}{dx}=\frac{xy+3x-y-3}{xy-2x+4y-8}\)
So separate x and y terms
\(\displaystyle (xy-2x+4y-8) dy = (xy+3x-y-3)\) ugh I'm stuck:(
\(\displaystyle \frac{dy}{dx}=\frac{xy+3x-y-3}{xy-2x+4y-8}\)
So separate x and y terms
\(\displaystyle (xy-2x+4y-8) dy = (xy+3x-y-3)\) ugh I'm stuck:(