- #1
cdhotfire
- 193
- 0
This somehow seems easy, but I cannot get the jist of it.
f(x) = x^3 - x^2 - 4x + 4
The point (a,b) is on the graph of f and the line tangent to the graph at (a,b) passes through the point (0,-8) which is not on the graph of f. Find the values of a and b.
okay so, I've spent about an hour just on this part, this problem had 3 parts.
so i though, maybe, set the original with as and bs, so:
b= a^3 - a ^2 - 4a + 4
then maybe take the derivative
b'= 3a^2 - 2a - 4
so maybe
y-8=b'x
from there on it seems to get pretty nasty, doesn't seem like the type of problem, that should be this nasty.
maybe someone can shed some light on this.
thanks in advanced.
f(x) = x^3 - x^2 - 4x + 4
The point (a,b) is on the graph of f and the line tangent to the graph at (a,b) passes through the point (0,-8) which is not on the graph of f. Find the values of a and b.
okay so, I've spent about an hour just on this part, this problem had 3 parts.
so i though, maybe, set the original with as and bs, so:
b= a^3 - a ^2 - 4a + 4
then maybe take the derivative
b'= 3a^2 - 2a - 4
so maybe
y-8=b'x
from there on it seems to get pretty nasty, doesn't seem like the type of problem, that should be this nasty.
maybe someone can shed some light on this.
thanks in advanced.