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dashkin111
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Homework Statement
See attachment
Homework Equations
We are to assume the voltage drop across diodes is .7v (don't use the diode equation!).
The Attempt at a Solution
I first was assuming that both diodes were "on". Then my work is as follows:
V1 is the voltage directly above diode D1 (the left most diode)...
[tex]I+ \frac{V_{1}-.7-(-5)}{5k\Omega}=\frac{5-V_{1}}{10k\Omega}[/tex]
[tex]I+ \frac{.7-.7+5}{5k\Omega}=\frac{5-.7}{10k\Omega}[/tex]
[tex]I=-.57mA[/tex]
Now since I is negative, one of my assumptions is wrong? So now I assume the rightmost one is "off" (D2).So.. then
Solving for I
[tex]I = \frac{5-.7}{10k\Omega}[/tex]
[tex]I = .43 mA[/tex]
Solving for V
Well.. since there's no current, v=-5?
Am I approaching this correctly?
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