- #1
Lanthanum
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Homework Statement
Given that q is an eigenvalue of a square matrix A with corresponding eigenvector x, show that qk is an eigenvalue of Ak and x is a corresponding eigenvector.
Homework Equations
N/A
The Attempt at a Solution
I really haven't been able to get far, but;
If x is an eigenvector of A corresponding to q, then;
0=(A-qI)x
To complete the proof I need to use this equation to show that (Ak-qkI)x=0, and this is where I'm having trouble.
If anyone has time to help I would really appreciate it.