Solve Electrical Circuit Problem: Particular Solution

In summary, the conversation discussed a problem involving an electrical circuit with a resistance, capacitor, and voltage generator. The task was to determine the voltage using a differential equation and a complex guessing method. The experts advised starting with a guess of V=Acos(2t), but this resulted in no solution. It was suggested to add on new functions to the guess, and to also consider rewriting the equation in a different form.
  • #1
palaszz
3
0
Hi everybody. I've got kind of a problem solving the following problem, so really hope for some help. The task says:

--------------------------

The figure beneath shows an electrical circuit containing following components: a resistance R, a capacitor with the capacitance C and finally a voltagegenerator E with the voltage E(t)=cos(2t).

http://img573.imageshack.us/img573/7493/matafl4.jpg

Now the voltage can obviously be determined by this diff.equation:

- R*C*(dV(t)/dt)+V(t)=cos(2t).

------------------------------

Now my problem is to - with help from the complex guessing-method - to determine a particular solution for the differential equation, and to make use of this in order to give the total solution of the differential equation.

Furthermore, in which way will it impact the circuit if I make use og this particular solution and at the same time make R=1 and C=1 and V(0)=2 ?

Really hope that someone can help me getting started.
 
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  • #2
When you have a differential equation and it equals a function of t, usually that's where you want to start your guess.

So you have diff. eqn=cos(2t) here. Which means that in V(t) and dV/dt we are going to need cos(2t) . So start your guess with V=Acos(2t) where A is an arbitrary constant. Then we get Acos(2t)+2RCAsin(2t)=cos(2t). This requires A to be 0 and 1 simultaneously, so there's no solution. The key is to add on new functions to our guess. Do you see what we want our next guess to be?
 
  • #3
Note that you don't even need to use that method. Your equation can be rewritten in the form

V'(t) + kV(t) = k*cos(2t)

This is a linear equation with integrating factor ekt, so multiply both sides by that and you will have an exact derivative to integrate.
 

FAQ: Solve Electrical Circuit Problem: Particular Solution

What is a particular solution in an electrical circuit problem?

A particular solution in an electrical circuit problem is a specific solution to the problem that satisfies all of the given conditions and constraints. It is often used to find the values of the variables in the circuit and can be obtained through various methods such as using Kirchhoff's laws or applying circuit analysis techniques.

How is a particular solution different from a general solution?

A general solution in an electrical circuit problem is a set of equations that can be used to find any possible solution to the problem. On the other hand, a particular solution is a specific solution that satisfies all of the given conditions and constraints. A general solution may have multiple particular solutions, but a particular solution is unique.

What are some common methods for obtaining a particular solution in an electrical circuit problem?

Some common methods for obtaining a particular solution in an electrical circuit problem include using Kirchhoff's laws, applying circuit analysis techniques such as Ohm's law and nodal analysis, and using circuit simulators. The chosen method may depend on the complexity of the circuit and the available resources.

Can a particular solution be verified to be correct?

Yes, a particular solution can be verified to be correct by substituting the values of the variables in the circuit equations and checking if they satisfy all of the given conditions and constraints. Additionally, the solution can be tested through circuit simulations or by physically building the circuit and measuring the values.

Are there any limitations to using a particular solution in an electrical circuit problem?

One limitation of using a particular solution in an electrical circuit problem is that it may not account for all possible scenarios or variations in the circuit. It is important to carefully analyze the given conditions and constraints to ensure that the particular solution obtained is applicable in all cases. Additionally, the accuracy of the particular solution may also be affected by factors such as measurement errors and component tolerances.

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