Solve Equation 5x - ||v|| v = ||w||(w-5x)

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In summary: But in this case, the equations can be solved for x, y, and z, respectively, and then these values can be checked by substituting them into the equations. In summary, we are asked to solve the equation 5x - ||v|| v = ||w||(w-5x) for x with given values of v and w, which can be done by substituting the values into the equation and solving for x.
  • #1
Fernando Revilla
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I quote an unsolved question from MHF posted by user Civy71 on February 18th, 2013
Solve the equation 5x - ||v|| v = ||w||(w-5x) for x with v = (1, 2, -4, 0) and w = (-3, 5, 1, 1)
 
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  • #2
We have:

$
\begin{aligned}5x-||v||v=||w||(w-5x)&\Leftrightarrow 5x+5||w||x=||w||w+||v||v\\&\Leftrightarrow 5(1+||w||)x=||w||w+||v||v\\&\Leftrightarrow x=\dfrac{1}{5(1+||w||)}(||w||w+||v||v)
\end{aligned}
$

Now, substitute $v=(1, 2, -4, 0)$, $w=(-3, 5, 1, 1 )$, $||w||=6$, $||v||=\sqrt{21}$.
 
  • #3
Personally, I would have immediately substituted the given values for v and w.

5x - ||v|| v = ||w||(w-5x) for x with v = (1, 2, -4, 0) and w = (-3, 5, 1, 1)
so [tex]||v||= \sqrt{1+ 4+ 16}= \sqrt{21}[/tex] and [tex]||w||= \sqrt{9+ 25+ 1+ 1}= \sqrt{38}[/tex]

Let x= (w, x, y, z) so the equation becomes
[tex](5w, 5x, 5y, 5z)- (\sqrt{21}, 2\sqrt{21}, -4\sqrt{21}, 0)= (-3\sqrt{38}, 5\sqrt{38}, \sqrt{38}, \sqrt{38})- (5\sqrt{38}w, 5\sqrt{38}x, 5\sqrt{38}y, 5\sqrt{38}z)[/tex]
which gives the four numeric equations
[tex]5w- \sqrt{21}= -3\sqrt{38}- 5\sqrt{38}w[/tex]
[tex]5x- 2\sqrt{21}= 5\sqrt{38}- 5\sqrt{38}x[/tex]
[tex]5y+ 4\sqrt{21}= \sqrt{38}- 5\sqrt{38}y[/tex]
[tex]5z= \sqrt{38}- 5\sqrt{38}z[/tex]
 
  • #4
HallsofIvy said:
Personally, I would have immediately substituted the given values for v and w.

All right, no problem with that. My preference was for the sake of generalization.
 
  • #5


To solve this equation, we will first need to define the notation used. ||v|| represents the magnitude or length of the vector v, which is calculated by taking the square root of the sum of the squares of its components. In this case, ||v|| = √(1^2 + 2^2 + (-4)^2 + 0^2) = √21. Similarly, ||w|| = √(3^2 + 5^2 + 1^2 + 1^2) = √36 = 6.

Substituting these values into the equation, we get:

5x - √21(1, 2, -4, 0) = 6(-3, 5, 1, 1 - 5x)

Expanding the equation, we get:

5x - (√21)(1, 2, -4, 0) = (-18, 30, 6, 6) + (30x, -50x, -10x, -10x)

Combining like terms, we get:

5x - (30x, -50x, -10x, -10x) = (-18, 30, 6, 6) + (√21)(1, 2, -4, 0)

Simplifying, we get:

-25x = (-18 + √21, 30 - 2√21, 6 + 4√21, 6)

Dividing both sides by -25, we get:

x = (18 - √21)/25, (2√21 - 30)/25, (4√21 - 6)/25, -6/25

Therefore, the solution to the equation is x = (18 - √21)/25, (2√21 - 30)/25, (4√21 - 6)/25, or -6/25.
 

FAQ: Solve Equation 5x - ||v|| v = ||w||(w-5x)

How do I solve the equation 5x - ||v|| v = ||w||(w-5x)?

To solve this equation, you will need to use algebraic manipulation and properties of absolute values. Start by distributing the ||w|| and ||v|| to get 5x - ||v||^2v = ||w||w - 5||w||x. Then, rearrange the equation to isolate the variable x. Finally, use the definition of absolute value to solve for x.

What do the absolute value symbols mean in this equation?

The absolute value symbols, || ||, indicate the magnitude or distance of a numerical value from zero. In this equation, they are used to ensure that the values inside are positive, which is necessary for solving the equation.

Can this equation be solved without using absolute values?

Yes, it is possible to solve this equation without using absolute values. However, using absolute values can make the process simpler and more straightforward.

What are some common mistakes when solving this equation?

One common mistake is forgetting to distribute the absolute values. Another is not rearranging the equation to isolate the variable x. It is also important to pay attention to signs and make sure they are carried over correctly when simplifying the equation.

Is there a specific method or formula for solving this type of equation?

There is no specific formula for solving this equation, but it involves using algebraic manipulation and properties of absolute values. It may also require some knowledge of solving linear equations and simplifying expressions.

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