- #1
bos1234
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Homework Statement
I've solved this question but I don't understand the conclusion the book says.
Question reads:
2 towers(transmitter and receiver), both of equal height(10m) and separated by a distance of 500m. f=800Mhz. Calculate first fresnel zone
First Fresnel zone has a radius of 6.84m at the midway point.
Then it further says that,
at a distance of 100m from either the transmitter or receiver, the first fresnel zone has a radius of 5.48m. Consequently,all objects between the txer and rxer must be shorter than 3-4m in order to have the approximate equivalent free-space propagaion over the 500m path at 800MHz.
Firstly, when they say that "at a distance of 100m from either the transmitter or receiver" does that mean the dist. between reciever and txer is 100m? If so I am getting 3.06 instead of 5.48m
Secondly, what's the point of finding this when the 2 towers are located 500m from each other>
relevant formula:
http://en.wikipedia.org/wiki/Fresnel_zone
F_n=...