Solve for Bmax: Quick Faraday Equation with Transformer Parameters

[kishanpatel50]

I have this equation and the following values for a transformer

B_max= (V₁)/(4N₁fA)

V₁=10v, i.e. 20v peak-to-peak
N₁=40 turns
f=5000Hz
A=76x10^-6 m²

When i substitute in the voltage, do i use the 10v, or the peak to peak, or would i have to convert to V_rms

 

[Bob S]

the Faraday equation is

V_peak= (2 pi f) B_peak A N

So B_peak= 10/(6.28 f A N) = 0.104 Tesla

 

[oswaler]

In this equation, V1 represents the peak-to-peak voltage, so you would use the 20V value. However, it is important to note that the equation for Bmax assumes an ideal transformer with no losses. In reality, the actual Bmax value may be lower due to losses in the transformer. Additionally, please note that the units for Bmax in this equation are Tesla (T). If you need to convert to another unit, such as Gauss (G), you will need to use a conversion factor.