It's not at all clear what you mean by "sin-(cos(17pi/5)". do you mean 'sine or cosine of that'? And, of course the "=" in "cos=" is a typo.Karma said:sin-(cos(17pi/5))
cos=(x+n2pi)=cos(x)
It's not at all clear what you mean by "sin-(cos(17pi/5)". do you mean 'sine or cosine of that'? And, of course the "=" in "cos=" is a typo.Karma said:sin-(cos(17pi/5))
cos=(x+n2pi)=cos(x)
"Int" stands for "integer," which is a whole number with no fractional or decimal part. In this equation, we are solving for the integer values of x that satisfy the given cosine function.
The general process for solving equations involving trigonometric functions is to use inverse trigonometric functions to isolate the variable and then solve for it. In this case, we would use the inverse cosine function (arccos) to find the value of x that satisfies the equation.
Yes, there can be more than one solution to this equation. Since cosine is a periodic function, it has multiple solutions for a given input. In this case, there are infinitely many solutions for x that satisfy the equation.
You can check your solution by plugging it back into the original equation. If the resulting equation is true, then your solution is correct. Additionally, you can use a graphing calculator to visually see where the two functions intersect, which would represent the solutions to the equation.
No, this equation cannot be solved algebraically. In most cases, equations involving trigonometric functions cannot be solved algebraically and require the use of inverse trigonometric functions or a graphing calculator to find the solutions.