- #1
y90x
- 47
- 0
Homework Statement
A worker is going to attempt to pull a 90-kg box across a level floor by a rope that makes an angle of 35° with the floor. The tension in the rope is gradually increased until the box just starts to move. If the coefficient of kinetic friction is 0.36 and the coefficient of static friction is 0.41 How much tension is in the rope when the block just starts to move?
Homework Equations
I’m guessing F=ma
The Attempt at a Solution
This is my work , however I thought I was doing it right but when I input in calculator I get the wrong answer. What am I doing wrong ?
U= mew (I believe that’s how it’s spelled)
Us(mg-Tsin(pheta))=Tcos(pheta)
Us(mg) - Us(Tsin(pheta))=Tcos(pheta)
Us(mg)=Tcos(pheta) + UsTsin(pheta)
T=(Us(mg))/(cos(pheta)-Ussin(pheta))
T=(0.41•90•9.8)/(cos35-0.41sin35)
T=619.2 N
The answer should be 343 Nhttps://www.physicsforums.com/attachments/215558