- #1
cshum00
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Homework Statement
So, i am given [tex]3^x(2x) = 3^x + 2x + 1[/tex]
And i want to solve for x.
Homework Equations
I only know that the solution is x=1 but i don't know how to get there.
The Attempt at a Solution
[tex]3^x(2x) = 3^x + 2x + 1[/tex]
[tex]3^x(2x) - 3^x = 2x + 1[/tex]
[tex]3^x(2x - 1) = 2x + 1[/tex]
[tex]3^x = \frac{2x + 1}{2x - 1}[/tex]
[tex]log(3^x) = log(\frac{2x + 1}{2x - 1})[/tex]
[tex]3log(x) = log(2x + 1) - log(2x - 1)<- typo[/tex]
[tex]xlog(3) = log(2x + 1) - log(2x - 1)[/tex]
And then i am stuck.
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