That's a good start. Then move all your log terms to one side and add 3 to both sides.tpent said:Homework Statement
log2(x3)-3= 2log2x
Homework Equations
None
The Attempt at a Solution
Do I start by expanding the x to the power 3 to the log which then makes it 3log2x? or am I totally off track?
Any help is greatly appreciated. Thanks
A logarithm is the inverse operation of exponentiation. It is used to solve for the exponent in an exponential equation. In other words, it tells you what power you need to raise a base number to in order to get a given result.
To solve for x in a logarithm question, you can use the exponentiation property of logarithms. This states that logb(x) = y is equivalent to by = x. In other words, you can rewrite the logarithm as an exponential equation and solve for x.
The most commonly used bases in logarithms are 10, e (Euler's number), and 2. Logarithms with base 10 are called common logarithms, while those with base e are called natural logarithms. Logarithms with base 2 are used in computer science and information theory.
Yes, you can still solve for x even if the base of the logarithm is different than the number. You can use the change of base formula which states that logb(x) = loga(x) / loga(b). This allows you to convert the logarithm to a different base and solve for x.
Yes, there are some restrictions when solving for x in a logarithm question. The argument (the number inside the parentheses) of the logarithm must be a positive real number. Additionally, the base of the logarithm must be a positive real number that is not equal to 1. If these conditions are not met, the logarithm is undefined and cannot be solved for x.