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hunter457
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Homework Statement
Billy has caught two fish. He has tied the line holding the 4.40kg trout to the tail of the 2.36kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 71.3 N. What is the tension of the rope connecting the trout and carp?
Homework Equations
Fy=ma,
The Attempt at a Solution
m=(mCARP+mTROUT), FA=applied force, FT=force of tension
Carp:
Fy=ma
FA-mg-FT=ma
71.3-(2.36+4.40)(9.8)-FT=(2.36+4.40)a
5.052-FT=6.76a
a=(5.052-FT)/6.76
Trout:
Fy=ma
FT-mg=ma
FT-(2.36+4.40)(9.8)=(2.36+4.40)a
FT-66.248=6.76a
a=(FT-66.248)/6.76
a=a, so:
(5.052-FT)/6.76= (FT-66.248)/6.76
5.052-FT=FT-66.248
5.052+66.248=FT+FT
71.3=2FT
FT=35.65N=35.6N
***My online assignment says that this answer is wrong***