- #1
Vrbic
- 407
- 18
Hello,
I have a problem with solution this equation: [itex]\frac{dy}{dx}=\sin{\frac{y}{x}} [/itex]. I tried to employ substitution [itex]u=\frac{y}{x}[/itex]. From this comming [itex]x\frac{du}{dx}=\sin{u}-u[/itex]. But than integration [itex]\int=\frac{1}{\sin{u}-u}[/itex] and I don't know if it is possible to solve it or all this way is wrong.
Thank you for comment or advice.
I have a problem with solution this equation: [itex]\frac{dy}{dx}=\sin{\frac{y}{x}} [/itex]. I tried to employ substitution [itex]u=\frac{y}{x}[/itex]. From this comming [itex]x\frac{du}{dx}=\sin{u}-u[/itex]. But than integration [itex]\int=\frac{1}{\sin{u}-u}[/itex] and I don't know if it is possible to solve it or all this way is wrong.
Thank you for comment or advice.