- #1
-Physician
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Homework Statement
A ball horizontally with an initial velocity of 5m/s,and the ball stops at 8.0m. Find the force of friction if the coefficient is 0.3.
Homework Equations
##F_net=ma##
##v^2=v_0^2 2ax##
## a=\frac{v_1^2 - v_0^2}{2ax}##
##f=μN##
##N=mg## (In this case the normal force is equal to weight.)
The Attempt at a Solution
## a=\frac{v_1^2 - v_0^2}{2ax}=\frac{-25\frac{m^2}{s^2}}{16m}=-1.56\frac{m}{s^2}##
##F_net=ma##
##f=ma##
##μN=ma##
##μmg=ma##
##μg=a##(Masses cancel out because the mass doesn't matter on rotary bodies.
##μg=a## I'm stuck here, how can I find the friction?!
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