Solve Fun Power Question: Frictional Force & Velocity

  • Thread starter Panphobia
  • Start date
  • Tags
    Fun Power
In summary, the conversation revolved around a question on power from an old physics exam. The individual drew a free body diagram and used Newton's Second Law to find that the driving force must overcome the frictional force. However, they were unsure how to solve for velocity with two unknowns and one equation. The conversation then shifted to deriving an expression for power, which was eventually calculated to be 104 kW or 140 hp.
  • #1
Panphobia
435
13

Homework Statement


Found a pretty fun question on power from one of my friends old physics exams just wanted to see if I was doing it right so far.

The Attempt at a Solution


So the first thing I did was draw a free body diagram and used Newtons Second law so

ƩFx: F - (250 + 0.7v^2) - mgsin10 = ma

Says that the driving force F must overcome the frictional force, so then ma = 0 and F = 250 + 0.7v^2 + mgsin10. A little stumped here, I am trying to find out the velocity, but I have two unknowns and one equation (please don't give me the answer, I want to solve it myself)!
 
Last edited:
Physics news on Phys.org
  • #2
Hi Panphobia! :smile:

(try using the X2 and X2 buttons just above the Reply box :wink:)
Panphobia said:
… ƩFx: F - (250 + 0.7v^2) - mgsin10 = ma

Says that the driving force F must overcome the frictional force, so then ma = 0 and F = 250 + 0.7v^2 + mgsin10. A little stumped here, I am trying to find out the velocity, but I have two unknowns and one equation …

I'm confused … the question says a = 1 and v = 27. :confused:
 
  • #3
But that is initial, the v is always changing, and in my head I was thinking that there is a maximum velocity because of the air resistance. Oh my was I overthinking that? But anyway I was actually talking about deriving an expression for the power P that is required to drive the wheels. The other part is pretty easy.
 
Last edited:
  • #4
Then F = 1150 + 250 + 0.7(27)^2 + (1150)(9.8)sin10
P = Fv
P = 3867.3*27
= 104 kW or 140 hp

Deriving would just be without numbers right?
 
  • #5
Panphobia said:
Then F = 1150 + 250 + 0.7(27)^2 + (1150)(9.8)sin10
P = Fv
P = 3867.3*27
= 104 kW or 140 hp

(i haven't checked your calculations, but …)

yes, those equations look correct :smile:
Panphobia said:
… I was actually talking about deriving an expression for the power P that is required to drive the wheels.
Deriving would just be without numbers right?

an expression would be without numbers, yes :wink:
 

FAQ: Solve Fun Power Question: Frictional Force & Velocity

What is frictional force?

Frictional force is a resistive force that opposes the motion of an object. It is caused by the interaction between two surfaces in contact with each other.

How does frictional force affect velocity?

Frictional force acts in the opposite direction of an object's motion, which causes it to slow down. This decrease in velocity is directly proportional to the amount of frictional force acting on the object.

Can frictional force ever increase velocity?

No, frictional force always acts in the opposite direction of an object's motion, so it can never increase velocity. It can only cause a decrease in velocity.

How does surface texture affect frictional force?

The rougher the surface, the greater the frictional force. This is because rough surfaces have more contact points between them, resulting in a stronger resistive force.

Is frictional force always constant?

No, frictional force can vary depending on the surfaces in contact and the amount of force applied. For example, the frictional force between two objects will be greater if more force is applied to them.

Back
Top