Solve Gas Law Problems: Volumes, Pressures, & Temperatures

[DoctorReynaldo]

Gas Law Problems
A gas-filled balloon occupies a 4-L volume at a pressure of 300kPa. What volume will the balloon occupy if it rises to a height of where the pressure is 200kPa?

Calculate the hieght to which a pressure of one atmosphere can life a column of water. Mercury is 13.6 times as dense as water.

a 60-m^3 volume of gasy is at a temperature of 27 degrees Celsius. Under constant pressure the gas is cooles to -73 degrees Celsius. Calculate the new volume of gas.

While held at a constant pressure, 12 L of gas are heated at 127.5 degrees celsius. If the new volume is 18L, what was the original temperature of the gas in degrees celsius?

A gas is kept in a closed container at 620kPa. The gas is heated from 100 degrees celsius to 300 degrees celsius. Calculate the new pressure of the gas.

a 6.0-L volume of gas has a pressure of 140 kPa and a temperature of -14 degrees celsius. What will be the pressure of this gas if the volume is reduced to 1.5 L and the temperature raised to 504 degrees celsius?

The density of air is 1.3g/L at standard conditions of 101 kPa and 0 degrees celsius. Determine the mass of 3.0 L of ait at a pressure of 138.2 kPa and a temperature of 273 degrees celsius.

One atmosphere of air pressure supports a column of water approximately 10.3 m high. A 2.0 cm^3 bubble of air is released by a diver working 62.4 m below the surface of a deep lake. If its temperature remains constant, what is the volume of the bubble as it reaches the surface? Hint: the pressure on the surface of the lake is on atm.

 

[On Radioactive Waves]

I think these can all be solved using the ideal gas law, pv=nrt

Since you didn't ask specificly for direction and have shown no work, this is about the most help you can expect to get here.


Hint:

Calculate the hieght to which a pressure of one atmosphere can life a column of water. Mercury is 13.6 times as dense as water.

and the answer is in another problem:

One atmosphere of air pressure supports a column of water approximately 10.3 m high.

 

[bramms0525]

I just got done with this lesson in chemistry. Most of those can be solved using the Boyle's Law and Combined Gas Law.

boyle's law - P1/P2 = V2/V1

Combined gas law - P1V1/T1 = P2V2/T2


P-Pressure
V-Volume
T-Temperature

*You might have to get P1 by using PG=Patm-Hg or PG=Patm-Hg-H2O

*Remember to change Celsius to Kelvins (C + 273)

There's some problems on there I don't know how to do.

I don't know why this is on a general physics forum. I've haven't had
physics yet. Am I going to see Gas Law again?