Solve Integral Problem: dy/dx=7sec^2(pix/4)tan(pix/4), y'(1)=0, y(1)=5

  • Thread starter Chas3down
  • Start date
  • Tags
    Integral
See if you can find anything else...In summary, the derivative of d2y/dx2 is 7sec^2(pix/4)tan(pix/4) and the given values for y'(1) and y(1) are 0 and 5 respectively. The first derivative is equal to 14/pi tan^2(pix/4) - 14/pi and the equation for y is 56tan(pix/4)/pi^2 - 56(pix/4)/pi^2 - 14x/pi + 5 - 56/pi^2 + 28/pi.
  • #1
Chas3down
60
0

Homework Statement


d2y/dx2 = 7sec^2(pix/4)tan(pix/4)
y'(1)=0
y(1)=5


Homework Equations





The Attempt at a Solution



dy/dx = 14/pi sec^2(pix/4)-28/pi
y = 56tan(pix/4)/pi^2-28x/pi+5-56/pi^2+28/pi


Not sure where I went wrong, but I checked on my calc and it wasn't equal.
 
Physics news on Phys.org
  • #2
The first derative should be something with tan^2(..).
 
  • #3
1 + tan^2(...) = sec^2(...) but 1 is just part of c

EDIT:

dy/dx = 14/pi tan^2(pix/4) - 14/pi

y = 56tan(pix/4)/pi^2 - 56(pix/4)/pi^2 - 14x/pi + 5 - 56/pi^2 + 28/picould anyone check this please?
 
Last edited:
  • #4
Chas3down said:
1 + tan^2(...) = sec^2(...) but 1 is just part of c

EDIT:

dy/dx = 14/pi tan^2(pix/4) - 14/pi

y = 56tan(pix/4)/pi^2 - 56(pix/4)/pi^2 - 14x/pi + 5 - 56/pi^2 + 28/pi


could anyone check this please?

Looks right, but you can simplify a little. Two terms are the same.
 

FAQ: Solve Integral Problem: dy/dx=7sec^2(pix/4)tan(pix/4), y'(1)=0, y(1)=5

1. What is the meaning of the given differential equation?

The given differential equation represents the rate of change of the function y with respect to x. The function y is dependent on the variable x and the equation shows that the rate of change of y is equal to 7 times the secant squared of pi times x divided by 4, multiplied by the tangent of pi times x divided by 4.

2. How can we solve this integral problem?

To solve this integral problem, we can use the technique of separation of variables. This involves isolating the variables dy and dx on opposite sides of the equation and then integrating both sides. This will give us the antiderivative of y with respect to x, which we can then use to find the specific solution to the given initial value problem.

3. What is the significance of the given initial conditions?

The initial conditions y'(1)=0 and y(1)=5 serve as boundary conditions for the general solution of the differential equation. These conditions specify the value of the function y at a particular point (x=1) and the rate of change of y at that point. These conditions are important in finding the specific solution to the given differential equation.

4. Can we use any other method to solve this integral problem?

Yes, there are other methods that can be used to solve this integral problem. One alternative method is using the method of substitution, where we substitute a new variable for the given expression and then integrate using the new variable. Another method is using the method of partial fractions, where we break down the given expression into simpler fractions and then integrate each term separately.

5. What is the final solution to this integral problem?

The final solution to this integral problem will be the specific solution to the given initial value problem. It will be in the form of a function y(x) that satisfies the given differential equation and the initial conditions. The solution will also include any arbitrary constants that arise during the integration process. In this case, the final solution will be a function of x that satisfies the equation y(x)= 5 + 7tan(pi*x/4) + C, where C is an arbitrary constant.

Back
Top