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apoptosis
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Hello
Here is an integral question I have. It's a surface area problem, but i just have issues simplifying the square root before solving. Any help appreciated!
y=(1-x[tex]^{2/3}[/tex])[tex]^{3/2}[/tex], 0[tex]\leq[/tex]x[tex]\leq[/tex]1
My work:
dy/dx=-x[tex]^{-1/3}[/tex](1-x[tex]^{2/3}[/tex])[tex]^{1/2}[/tex]
(dy/dx)[tex]^{2}[/tex]=-x[tex]^{-2/3}[/tex](1-x[tex]^{2/3}[/tex])
=-x[tex]^{-2/3}[/tex]+1
S=(insert integral with limits here) 2[tex]\pi[/tex]xds
=2[tex]\pi[/tex]x [tex]\sqrt{-x^{-2/3} +1+1}[/tex]
=2[tex]\pi[/tex]x [tex]\sqrt{-x^{-2/3} +2}[/tex]
I'm not sure where to go after this...
thx
Here is an integral question I have. It's a surface area problem, but i just have issues simplifying the square root before solving. Any help appreciated!
y=(1-x[tex]^{2/3}[/tex])[tex]^{3/2}[/tex], 0[tex]\leq[/tex]x[tex]\leq[/tex]1
My work:
dy/dx=-x[tex]^{-1/3}[/tex](1-x[tex]^{2/3}[/tex])[tex]^{1/2}[/tex]
(dy/dx)[tex]^{2}[/tex]=-x[tex]^{-2/3}[/tex](1-x[tex]^{2/3}[/tex])
=-x[tex]^{-2/3}[/tex]+1
S=(insert integral with limits here) 2[tex]\pi[/tex]xds
=2[tex]\pi[/tex]x [tex]\sqrt{-x^{-2/3} +1+1}[/tex]
=2[tex]\pi[/tex]x [tex]\sqrt{-x^{-2/3} +2}[/tex]
I'm not sure where to go after this...
thx
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