Solve Kinematic Problem: Ball Falls 1.52m from Table

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In summary, to calculate the time it takes for a ball to fall 1.52m from a table, we can use the formula t = square root of (2h/g), where t is time, h is height (1.52m in this case), and g is the acceleration due to gravity (9.8 m/s²). This will give us a result of 0.55 seconds. The velocity of the ball can be calculated using the formula v = gt, where v is velocity, g is acceleration due to gravity (9.8 m/s²), and t is the calculated time. The position of the ball at any given time during its fall can be determined using the formula s = ut + 1/
  • #1
assaftolko
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A ball moves to the edge of a table which is 1.2 m above ground. The ball falls off and hits the ground 1.52 m horizontly from the edge of the table.

(a) How much time does it take the ball to hit the ground?
(b) What's the ball initial velocity?

Am I to understand that the initial velocity is only horizontly (Vo,x)? Because if it's not I don't know its size, the angle it creates with the horizon and the time factor... 3 variables with 2 equations...
 
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  • #2
Yes, assume the initial velocity is horizontal.
 
  • #3
thanks!
 

FAQ: Solve Kinematic Problem: Ball Falls 1.52m from Table

How do you calculate the time it takes for the ball to fall 1.52m from the table?

To calculate the time, we can use the formula t = square root of (2h/g), where t is time, h is the height (1.52m in this case), and g is the acceleration due to gravity (9.8 m/s²). Plugging in the values, we get t = square root of (2*1.52/9.8) = 0.55 seconds.

What is the velocity of the ball as it falls from the table?

The velocity of the ball can be calculated using the formula v = gt, where v is the velocity, g is the acceleration due to gravity (9.8 m/s²), and t is the time calculated in the previous step (0.55 seconds). Plugging in the values, we get v = 9.8*0.55 = 5.39 m/s.

How can we determine the position of the ball at any given time during its fall?

To determine the position of the ball at any given time, we can use the formula s = ut + 1/2gt², where s is the position, u is the initial velocity (0 m/s), g is the acceleration due to gravity (9.8 m/s²), and t is the time. Plugging in the values, we get s = 0*0.55 + 1/2*9.8*(0.55)² = 0.75 m. This means that after 0.55 seconds, the ball will have fallen 0.75 meters from the table.

What other factors can affect the motion of the ball as it falls from the table?

Apart from the acceleration due to gravity, other factors that can affect the motion of the ball include air resistance, the shape and size of the ball, and the surface it is falling on. These factors may cause the ball to deviate from the calculated motion, making the results less accurate.

How can we use this kinematic problem to solve real-life situations?

This kinematic problem can be applied in various real-life situations, such as calculating the time it takes for an object to fall from a certain height, determining the velocity of a falling object, and predicting the position of an object at any given time during its fall. This can be useful in fields such as engineering, physics, and sports, where understanding the motion of objects is important.

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