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nobodyuknow
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Homework Statement
Laplace transform: te^t*H(t-1)
Homework Equations
L{te^t} = 1/(s-1)^2
L{H(t-1)} = e-s/s
The Attempt at a Solution
Using e^(at)f(t) -> F(s-a)
with..e^(1t)H(t-1)
We can get, e^(-1s-1)/(s-1) = e^(-s-1)/(s-1) [I think?]
Thus applying tf(t) -> -dF/ds
Derive[e^(-s-1)/(s-1)] w.r.t. s, you get:
-se^(-s-1)/(s-1)^2
Which is close, but, not exact.
I know the answer is se^s-1/(s-1)^2
But how do they come to that?
I don't think the order of my working would affect the final outcome.
All help appreciated
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