Solve Linear Systems: Determine Critical Point Stability

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In summary, The conversation was about reviewing differential equations and how to determine phase plane stability in systems of differential equations. The homework question was to solve a linear system and determine whether the critical point (0,0) is stable, asymptotically stable, or unstable. The equations given were dx/dt=2x and dy/dt=-2y. The attempt at a solution involved trying to solve the equations without using MATLAB and asking for help. The expert summarizer explained that solving the equations separately reveals an unstable equilibrium and also provided a more general method for determining stability.
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forest125
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Wanted to brush up on my diff equations a bit. I have kind of forgotten how to determine phase plane stability in systems of differential equations.

Homework Statement


Solve linear systems. Determine whether the critical point (0,0) is stable, asymptotically stable, or unstable.

dx/dt=2x and dy/dt=-2y

Homework Equations



Not sure there's anything for this section...

The Attempt at a Solution



Well 2x=0 and -2y=0 only yields a 1 CP of (0,0). Without using MATLAB or something, I'm really not sure how to do this numerically. Help anyone?

Thank you much.
 
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Do what numerically? Surely, you didn't need MatLab to solve 2x= 0 and -y= 0!

If fact, it is not difficult to solve the two equations separately. If dx/dt= 2x, then dx/x= 2dt and, integrating, ln(x)= 2ln(t)+ C= ln(t^2)+ C so that x= C't^2. Obviously, as t goes to infinity, so does x so this is an unstable equilibrium.

More generally, if you have dx/dt= ax+ by, dy/dt= cx+ dy, you would look at the eigenvalues of the matrix
[tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}[/tex]

If the real part of any of the eigenvalues is positive, the equilibrium is unstable. If all eigenvalues have negative real part, the equilibrium is asymptotically stable, if any of the eigenvalues have 0 real part and the others negative, the equilibrium is stable.
 

FAQ: Solve Linear Systems: Determine Critical Point Stability

1. What is a linear system?

A linear system is a set of equations that can be written in the form of n equations with n unknown variables, where each equation is a linear combination of the variables. In other words, each equation can be expressed as a sum of multiples of the variables.

2. How do you solve a linear system?

There are several methods for solving a linear system, including substitution, elimination, and graphing. The most commonly used method is Gaussian elimination, which involves using elementary row operations to transform the system into an equivalent system with a triangular or diagonal structure, making it easier to solve.

3. What are critical points in a linear system?

Critical points are points on the graph of a linear system where the slope is either zero or undefined. In other words, they are points where the system has no unique solution or where the solution changes dramatically.

4. How do you determine the stability of a critical point?

To determine the stability of a critical point, you need to analyze the behavior of the system near that point. This can be done by finding the eigenvalues of the coefficient matrix, which will tell you whether the critical point is stable, unstable, or a saddle point.

5. Why is it important to determine the stability of a critical point?

Determining the stability of a critical point is important because it can tell you about the long-term behavior of the system. A stable critical point means that the system will eventually reach an equilibrium state, while an unstable or saddle point indicates that the system will not reach a stable solution and may exhibit chaotic behavior.

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