MHB Solve Logarithmic Equation: 7(3+7x)-3(4-2x)=0

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To solve the logarithmic equation 7(3+7x) = 3(4-2x), take the logarithm of both sides. This transforms the equation into a linear form in terms of x. After applying logarithmic properties, standard methods can be used to solve for x. The approach simplifies the problem and allows for straightforward calculations. This method effectively resolves the logarithmic equation.
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i have the equation 7(3+7x) = 3(4-2x)

so, I tried 7(3+7x)-3(4-2x)=0

...
 
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datafiend said:
i have the equation 7(3+7x) = 3(4-2x)

so, I tried 7(3+7x)-3(4-2x)=0

...

Hi there datafiend,

Take the logarithm on both sides of the equation $7^{(3 + 7x)} = 3^{(4 - 2x)}$. This will give you a linear equation in $x$, which you can solve by usual methods.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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