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jckjmes
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Homework Statement
A uniform ladder 5m long and of mass 40kg rests with its upper end against a smooth vertical wall and with its lower end 3m from the wall on rough ground. Find the magnitude and direction of the force exerted at the bottom of the ladder. (G=9.81ms^-2)
Homework Equations
ACM=CM
moment=force x distance from the pivot
The Attempt at a Solution
w(moment) = (40 x 9.81) x 2.5 =981 Nm clockwise
ACM=CM
therefore: reaction moment = 981Nm
and force = 981/3 =327N anticlockwise
Is this right or am i very far off??