- #1
jdawg
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Homework Statement
Use node voltage analysis to determine values for I1, I2, and I3. If a current has a negative value, then the reference direction chosen was incorrect and the current is positive in the opposite direction.
I attached a picture of the circuit. The things in blue (current ix and the nodes A and B) are what I put in the circuit when I was trying to solve it. They weren't in the original drawing of the circuit.
Homework Equations
The Attempt at a Solution
Assume currents entering a node are negative and currents leaving a node are positive. Assume voltage rise as positive and a voltage drop as negative.
I started by doing a nodal analysis at Node A:
-ix+ (VA-VRef)/(10)+(VA-VB)/(20)=0
ix=(28-VA)/(10)
Substituted in ix and then simplified to get this:
5VA-VB=56
Here's the part I'm not really confident about:
At node B:
(VB-VA)/(20)+(VB)/(5)=10mA
I keep getting a ridiculously small number. I guess it kind of makes since since I have mA and kΩ, but I just feel like I'm doing something wrong.
Thanks for any help!