Solve Problem in Mechanics Homework: Find Acceleration Angle

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In summary, the car starts from rest on a circular track. It increases its speed at a constant rate at every turn. The attempted solution was to find the angle that the car makes at the moment it completes the circle. The angle was found to be 4.548 degrees.
  • #1
the_storm
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Homework Statement


A race car starts from rest on a circular track. the car increases its speed at a constant rate at as it goes once around the track.


Homework Equations



Find the angle that the total acceleration of the car makes- with the radius connecting the centre of the track and the car- at the moment the car completes the circle.


The Attempt at a Solution


First I put the angle = [tex]\theta[/tex]
I put the total acceleration = a
and ar= a radial
and then I found that Cos[tex]\theta[/tex]=[tex]\frac{a r }{a}[/tex]
then I said ar=[tex]\frac{v2}{r}[/tex]
and v2=[tex]\frac{2 by r}{T}[/tex] where T is the period. But I stopped I have no numbers
So can anyone help me?
 
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  • #2
Do this: Call the tangential acceleration at. Use this to figure out the speed at the end of circle and thus ar. Use those components to find the angle. (Hint: Express everything in terms of the final speed and the radius.)
 
  • #3
Doc Al said:
Do this: Call the tangential acceleration at. Use this to figure out the speed at the end of circle and thus ar. Use those components to find the angle. (Hint: Express everything in terms of the final speed and the radius.)

Got it :)
thank you bro :D
 
  • #4
hey Doc Al am just typing the answer to make sure it is okay, cause I think there is something error because the final answer unreasonable
This what I have done
since at=[tex]\frac{Vf2}{2\pi r}[/tex]
and ar=[tex]\frac{vf2}{r}[/tex]
therefore tan[tex]\theta[/tex]= [tex]\frac{at}{ar}[/tex]
therefore tan[tex]\theta[/tex]= [tex]\frac{v2}{4\pi r}[/tex] × [tex]\frac{r}{v2}[/tex]
So [tex]\theta[/tex] = tan-1([tex]\frac{1}{4 \pi}[/tex]
So [tex]\theta[/tex] = 4.548 degrees
I think the angle is too small and it is incorrect ! ?
 
  • #5
the_storm said:
So [tex]\theta[/tex] = tan-1([tex]\frac{1}{4 \pi}[/tex]
So [tex]\theta[/tex] = 4.548 degrees
I think the angle is too small and it is incorrect ! ?
That answer sounds right to me.

FYI: Your formatting is getting messed up because you are using the sup and sub tags within Latex; keep them separate. The way to use subscripts in Latex is like a_r; to use superscripts, v^2.
 
  • #6
Ok thank you bro very much :)
 

FAQ: Solve Problem in Mechanics Homework: Find Acceleration Angle

What is acceleration angle in mechanics?

Acceleration angle in mechanics refers to the direction of acceleration in a given system. It is the angle between the direction of motion and the direction of acceleration. It is measured in radians or degrees and plays a crucial role in determining the overall acceleration of a body.

How do you find acceleration angle in mechanics?

To find the acceleration angle in mechanics, you can use the formula: tanθ = ay/ax, where θ is the acceleration angle, ay is the vertical component of acceleration, and ax is the horizontal component of acceleration. You can also use vector addition to find the resultant acceleration vector and then determine the angle using trigonometric functions.

What is the difference between acceleration angle and velocity angle?

The acceleration angle and velocity angle are both measured in relation to the direction of motion. However, the acceleration angle refers to the direction of acceleration, while the velocity angle refers to the direction of velocity. In simple terms, the acceleration angle shows the direction of change in velocity, while the velocity angle shows the direction of motion.

How does the acceleration angle affect an object's motion?

The acceleration angle plays a crucial role in determining an object's motion. If the acceleration angle is zero, the object will experience uniform motion. If the angle is greater than zero, the object will accelerate in the direction of the angle. If the angle is less than zero, the object will decelerate or accelerate in the opposite direction of the angle. In other words, the acceleration angle determines the direction and magnitude of an object's acceleration.

Can the acceleration angle ever be negative?

Yes, the acceleration angle can be negative. A negative acceleration angle indicates that the object is decelerating or accelerating in the opposite direction of the angle. This can happen when the object is slowing down or changing direction in a curved path. However, the magnitude of the acceleration will still be positive, as it represents the rate of change of velocity.

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